Span: the flat region of everything reachable from a generating set

Beginner Mathematics
Created by Best · 01.06.2026 at 06:20 UTC

$\mathrm{span}\{\mathbf{v}_1,\ldots,\mathbf{v}_k\}$ is the set of all destinations produced by some choice of coefficients. In $\mathbb{R}^3$, one nonzero vector spans a line; two non-collinear vectors span a plane; three independent vectors can reach the full space .

Watch dependence degeneracies: if every generator lies in a plane, no amount of scaling escapes that plane. Span is intrinsic to the generating set, not "whatever the drawing looks like." If $\mathbf{w}$ already lies in $\mathrm{span}\{\mathbf{u},\mathbf{v}\}$, then adding $\mathbf{w}$ does not enlarge the span.

The span of any set of vectors is always a subspace: closed under addition and scalar multiplication, and always containing $\mathbf{0}$. Two collinear nonzero vectors in $\mathbb{R}^3$ span only the line through the origin along their shared direction.

Example: $\mathrm{span}\{\hat{\mathbf{i}}\}$ in $\mathbb{R}^3$ is the $x$-axis, all vectors with second and third coordinates zero. That is a one-dimensional subspace even though the ambient space is three-dimensional .

Check your understanding. The tasks below rest on these ideas: Correct: a redundant generator adds no new reachable points, so the span is unchanged. Not quite: a dependent vector cannot suddenly reach all of space or collapse the span to a line or to nothing. Correct: by construction the span contains all combinations, so it is closed under the operations and holds the origin. Not quite: spans are continuous subspaces, contain rather than oppose their generators, and need not fill the whole space. Correct: collinear vectors are scalar multiples, so every combination stays on their shared line through $\mathbf{0}$. Not quite: a plane or all of space needs two or three independent directions, and a span is a continuum, not just the listed vectors. Correct: scaling $\hat{\mathbf{i}}$ alone reaches every $(t,0,0)$, a one-dimensional subspace. Not quite: a plane or all of space requires more independent directions, and the span is the whole line, not one point.

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Tasks
Question 1

If $\mathbf{w}$ already lies in $\mathrm{span}\{\mathbf{u},\mathbf{v}\}$, then $\mathrm{span}\{\mathbf{u},\mathbf{v},\mathbf{w}\}$ equals:

Hint

Skim the paragraphs on already lies then equals in Span before choosing. Eliminate options that contradict a definition stated in the card.

Question 2

The span of any set of vectors is always:

Hint

Skim the paragraphs on span vectors always in Span before choosing. Eliminate options that contradict a definition stated in the card.

Question 3

Two nonzero collinear vectors in $\mathbb{R}^3$ span:

Hint

Skim the paragraphs on nonzero collinear vectors span in Span before choosing. Eliminate options that contradict a definition stated in the card.

Question 4

What is $\mathrm{span}\{\hat{\mathbf{i}}\}$ inside $\mathbb{R}^3$?

Hint

Skim the paragraphs on inside in Span before choosing. Eliminate options that contradict a definition stated in the card.

Card Info
  • Topic: Mathematics
  • Difficulty: Beginner
  • Completed: 0 users
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